5h^2+7h-8=0

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Solution for 5h^2+7h-8=0 equation: 



5h^2+7h-8=0

a = 5; b = 7; c = -8;
Δ = b2-4ac
Δ = 72-4·5·(-8)
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{209}}{2*5}=\frac{-7-\sqrt{209}}{10}
$


$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{209}}{2*5}=\frac{-7+\sqrt{209}}{10}
$

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